x^2+.7x-14.1=0

Solution for x^2+.7x-14.1=0 equation:

x^2+.7x-14.1=0

a = 1; b = .7; c = -14.1;
Δ = b2-4ac
Δ = .72-4·1·(-14.1)
Δ = 56.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.7)-\sqrt{56.89}}{2*1}=\frac{-0.7-\sqrt{56.89}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.7)+\sqrt{56.89}}{2*1}=\frac{-0.7+\sqrt{56.89}}{2}
$